Matematika

Pertanyaan

Tentukan hasil dari ( tanpa menghitung satu per satu)
A. 2+4+6+8+10+...+100
B. -1+2-3+4-5+6-7+8-...+100
C. -100-99-98-...-2-1-0+1+2+...+97+98+99

1 Jawaban

  • Penyelesaian:

    A. 2 + 4 + 6 + 8 + ... + 100
    a = 2 
    b = 2

    Un = a + (n-1)b
    100 = 2 + (n-1)2
    n = 50

    Sn = n/2 (2a + (n-1)b)
    = 50/2 (2(2) + (50-1)2)
    = 25 (102)
    Sn = 2,550

    B. -1 + 2 - 3 + 4 - 5 + 6 - 7 + ... + 100
    dapat dipecah menjadi 2 barisan bilangan:
    barisan bilangan 1 = -1 - 3 - 5 - 7 - ... - 99
    a = -1 ; b = -2

    Un1 = a + (n-1)b
    -99 = -1 + (n-1)(-2)
    n = 50

    Sn = n/2 (2a + (n-1)b)
    = 50/2 (2(-1) + (50-1)(-2)
    = 25 (-100)
    Sn1 = -2,500

    barisan bilangan 2: 2 + 4 + 6 + 8 + ... + 100
    a = 2 ; b = 2

    Un = a + (n-1)b
    100 = 2 + (n-1)2
    Un2 = 50

    Sn2 = 50/2 (2(2) + (50-1)(2)
    = 25 (4 + 98)
    = 25 (102)
    Sn2 = 2,550 

    Sn2 - Sn1 = 2,550 - 2,500 = 50

    C. -100 - 99 - 98 - ... + 99
    a = -100 ; b = 1

    Un = a + (n-1)b
    99 = -100 + (n-1)(1)
    n = 200

    Sn = n/2 (2a + (n-1)b)
    = 200/2 (2(-100) + (200-1)(1)
    = 100 (-200 + 199)
    = 100 (-1)
    Sn = -100

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