Segitiga ABC dan CDE kongruen panjang EB=20cm panjang AC 7 cm tentukan panjang CB

CB = CD
AC = EC = 7 CM
EB = 20 CM ( BC + EC )

CB = EB - AC = 20 - 7 = 13

dik : EB =20
AC = 7
•sisi EB=AD
•sisi AC=CE
•sisi CB=CD
dit : CB?
jawab : CB = EB- AC
CB = 20-7
CB = 13 cm