Matematika

Pertanyaan

1. 2log6+2log18-2log22 =....
2. 3log9+3log√3-2³log27 =...

Tolong dong bantu saya ,plisss

1 Jawaban

  • 1. 2log6+2log18-2log22 =

    <==> 2 ( log 6 + log18 -log22)
    <==> 2 ( log (6x18) - log 22)
    <==> 2 ( log 108 - log 22 )
    <==> 2 ( log 108/22 )
    <==> 2 log4
    <==> log4^2
    <==> log 16

    2. 3log9+3log√3-2³log27 =

    <==> 3log3^2 + 3log3^1/2 - 2³log3^3
    <==> 6log3 + 3/2log3 - 6³log3
    <==> 15/2 log3 - 6

    Semoga membantu

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