tolong kerjakan  pakai penyelesaiannya yaa. 1)nilai Lim x⇒4 x²+8 = .... x+2 2) nilai lim x⇒1 x pangkat10 - 1 = ...... x-1 tolong bantuin yaa,makasihh

kalo cari limit yang x'nya memepunyai angka masukan terlebih dahulu xnya, (1) lim x -> 4. x^2 + 8/ x + 2 = 4^2 + 8/ 4 + 2 = 16 + 8/ 6 = 24/6 = 4, jadi lim x -> 4 = 4 (2) lim x -> 1, x^10 - 1/ x - 1 = 1^10 - 1/ 1 - 1 = 1 - 1/ 1 - 1= 0/0 jika hasilnya 0/0 maka dalil hospital lim x -> 1, x^10 - 1/ x - 1 = x^9/ 1 = 1^9/ 1 = 1/1 = 1, jadi lim x -> 1 = 1 #semoga membantu :)

1.
Limx⇒4 (x² + 8) / (x + 2)
= (4² + 8) / (4 + 2)
= (16 + 8) / 6
= 24 / 6
= 4

2.
Limx⇒1 (x^10 - 1) / (x - 1)
= Limx⇒1 (10x^9) / 1
= Limx⇒1 10x^9
= 10(1)^9
= 10 . 1
= 10