1.|x+5|<=|x-3| 2.|x-4|>|3x+2| 3.|4x-1|<|2x+3| 4.|10-3x|>=|x+2| 5.|7-5x|<=|9-2x|
Matematika
ardr1
Pertanyaan
1.|x+5|<=|x-3|
2.|x-4|>|3x+2|
3.|4x-1|<|2x+3|
4.|10-3x|>=|x+2|
5.|7-5x|<=|9-2x|
2.|x-4|>|3x+2|
3.|4x-1|<|2x+3|
4.|10-3x|>=|x+2|
5.|7-5x|<=|9-2x|
1 Jawaban
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1. Jawaban ZainuddinBms
2.) |x-4|>|3x+2|
{(x-4)+(3x+2)} {(x-4)-(3x+2)}
{(x-4+3x+2)} {(x-4-3x-2)}
{(4x-2) (-2x-6)}
4x-2=0 -2x-6=0
4x=0+2 -2x=0+6
4x=2 -2x=6
x=2 per 4 x=6 bagi -2
x= -3
Himpunan penyelesaian:
{ x< -3 atau x> 2 per 4 }
3.) |4x-1|<|2x+3|
{(4x-1)+(2x+3)} {(4x-1)-(2x+3)}
{(4x-1+2x+3)} {(4x-1-2x-3)}
{(6x+2) (2x-4)}
6x+2=0 2x-4=0
6x=0-2 2x=0+4
6x= -2 2x=4
x= -2 per 6 x=4 bagi 2
x=2
Himpunan penyelesaian;
{ -2 per 6 <x< 2}