Diketahui ^2 log 5=a dan ^5 log 3=b. Tentukan nilai 3 log 10?

3 log 10 = 3 log 5.2
              = 3 log 5 + 3 log 2
              = 1/ 5 log 3 + 1/ 2 log 3
              = 1/b + 1/ 2 log ₅.⁵ log 3
             = 1/b + 1/ab
             = a/ab + 1/ab
           

²log 5 = a <--> ^5 log 2 = 1/a
^5 log 3 = b


³log 10
= (^5 log 10) / (^5 log 3)
= (^5 log (5 x2)) / (b)
= (^5 log 5 + ^5 log 2) / b
= ( 1 + (1/a)) / b
= ( (a + 1) /a ) / b
= (a + 1)/ab