Materi logaritma Jawab dengan penjelasan

Materi Logaritma


[tex] \sqrt{3} ^{ ^9 \log 16} \\ \\ ^9 \log 16 = ^{3^2} \log 4^2 \rightarrow \frac{2}{2} \cdot ^3 \log 4 \rightarrow ^3 \log 4 \\\\ = (3^{\frac{1}{2}})^{ ^3 \log 4} \\\\ = 3^{ ^3 \log 4^{\frac{1}{2}} \\\\ = 3^{^3 \log 2} \\ = 2 [/tex]

Logaritma

akar 3 ^9 log 16
=akar 3^9 × 4 log 2
=3^0/2 × 4 log 2
=4 × 3^0/2 log 2
=2 ( D )