Matematika

Pertanyaan

sin a = 3/5 sin b = 12/13 maka tan (a-b)=

1 Jawaban

  • sin a = depan/miring = 3/5
    cari samping pake phytagoras

    samping² = 5²-3²
    samping² = 25-9
    samping² = 16
    samping = √16
    samping = 4

    tan a = depan/samping = 3/4

    sin b = 12/13

    cari samping =

    samping² = 13²-12²
    samping² = 169-144
    samping² = 25
    samping = √25
    samping = 5

    tan b = 12/5

    tan (a-b) = tan a-tan b = 3/4-12/5 = ....

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