sin a = 3/5 sin b = 12/13 maka tan (a-b)=
Matematika
ridhaalifiami
Pertanyaan
sin a = 3/5 sin b = 12/13 maka tan (a-b)=
1 Jawaban
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1. Jawaban wilimunchenesti
sin a = depan/miring = 3/5
cari samping pake phytagoras
samping² = 5²-3²
samping² = 25-9
samping² = 16
samping = √16
samping = 4
tan a = depan/samping = 3/4
sin b = 12/13
cari samping =
samping² = 13²-12²
samping² = 169-144
samping² = 25
samping = √25
samping = 5
tan b = 12/5
tan (a-b) = tan a-tan b = 3/4-12/5 = ....