Pertidaksamaan kelas X

Penyelesaian:

[tex] \frac{3}{x^2 - 3x + 2} \ \textless \ \frac{5}{x^2 - 4x + 3} [/tex]
= [tex] \frac{3}{(x-2)(x-1)} \ \textless \ \frac{5}{(x-3)(x-1)} [/tex]
= [tex] \frac{3}{(x-2)} \ \textless \ \frac{5}{(x-3)} [/tex]
= [tex] \frac{3}{(x-2)} - \frac{5}{(x-3)} \ \textless \ 0[/tex]
= [tex] \frac{3x - 9 - 5x + 10}{(x-2)(x-3)} \ \textless \ 0[/tex]
= [tex] \frac{-2x + 1}{(x-2)(x-3)} \ \textless \ 0[/tex]

maka nilai x yang mungkin: x = 1/2 ; x = 2 ; x = 3

gambar kan ke garis bilangan di dapat HP:

HP:{ 1/2 < x < 2 atau x > 3}