4 log 9 × 3 log 125 × 5 log 16 = .... Sederhanakanlah ...

⁴log9׳log125×5log16 =
=²log3׳log125×5log16
=²log125×5log16
=(³√2 log ³√125) × 5log16
=³√2log 5×5log16
=³√2 log 16
= 2^1/3 log 2⁴
= 4/(1/3) ²log2
= 12

4'log 9 × 3'log 125 × 5'log 16
= (2/2) . 2'log 3 × 3 . 3'log 5 × 4 . 5'log 2
= 12 . 2'log 2
= 12