Calculate the empirical formulae of the following compound. Please give solution

Stoichiometry

Ar Fe = 56
Ar O = 16

Mass of Fe = 11.2 grams
Mass of O = 16.0 - 11.2 = 4.8 grams

Ratio beween mass and Ar
Fe : O = [11.2/56] : [4.8/16]
Fe : O = 0.2 : 0.3
Fe : O = 2 : 3

Empirical formulae is Fe₂O₃