tolong jawab pakai cara.rasionalkan penyebut akar berikut:

[tex] \frac{2a}{3a + \sqrt{5} } = \frac{2a}{3a + \sqrt{5} } * \frac{3a - \sqrt{5}}{3a - \sqrt{5} } = \frac{6a^2 - 2a \sqrt{5 } }{9a^2 - 5} [/tex]

[tex]5 \sqrt{24} + 3\sqrt{3}( \sqrt{18} + 2 \sqrt{32}) = 10 \sqrt{6} + 3 \sqrt{3}(3 \sqrt{2} + 2*4) = [tex]10 \sqrt{6} + 9 \sqrt{6} + 24 \sqrt{3} = 19 \sqrt{6} + 24 \sqrt{3} [/tex]