Matematika

Pertanyaan

tolong bantu kerjakan. hari senin udah mau dikumpul. mohon bantuannya
tolong bantu kerjakan. hari senin udah mau dikumpul. mohon bantuannya

1 Jawaban

  • Penyelesaian:

    a. [tex] \int\limits^3_0 {2x^3 . 8x} \, dx [/tex]
    = [tex] \int\limits^3_0 {16x^4} \, dx [/tex]
    = [tex] \frac{16}{5} x^5 [/tex] ] 0->3
    = [tex] \frac{16}{5}(3)^5 - (0) [/tex]
    = [tex] \frac{16}{5}(243)[/tex]
    = [tex] \frac{3,888}{5} [/tex]

    b. [tex] \int\limits^5_2 {(2x - 1)(5x + 2)} \, dx [/tex]
    = [tex] \int\limits^5_2 {10x^2 - x - 2} \, dx [/tex]
    = [tex] \frac{10}{3}x^3 - \frac{1}{2}x^2 - 2x [/tex] ] 2->5
    = [tex] (\frac{10}{3}(5)^3 - \frac{1}{2}(5)^2 - 2(5)) - ( \frac{10}{3}(2)^3 - \frac{1}{2}(2)^2 - 2(2)) [/tex]
    = [tex]( \frac{1250}{3} - \frac{25}{2} - 10) - ( \frac{80}{3} - \frac{4}{2} - 4) [/tex]
    = [tex]( \frac{2500 - 75 - 60}{6} ) - ( \frac{160 - 12 - 24}{6} ) [/tex]
    = [tex] \frac{2365}{6} - \frac{124}{6} [/tex]
    = [tex] \frac{2241}{6} [/tex]