f'(x)= 4(x-5) (x+1) dan f(1)=10
Matematika
simama
Pertanyaan
f'(x)= 4(x-5) (x+1) dan f(1)=10
1 Jawaban
-
1. Jawaban Anonyme
f'(x) = 4(x - 5)(x + 1)
f'(x) = 4(x² - 4x - 5)
f'(x) = 4x² - 16x - 20
f(x) = ∫f'(x) dx
f(x) = ∫(4x² - 16x - 20) dx
f(x) = 4/3 x³ - 8x² - 20x + C
f(1) = 10
4/3 . 1³ - 8 . 1² - 20 . 1 + C = 10
4/3 - 8 - 20 + C = 10
C - 26 2/3 = 10
C = 10 + 26 2/3
C = 36 2/3
Jadi..
f(x) = 4/3 x³ - 8x² - 20x + 36 2/3