tebtukan rumus f(x) bila di ketahui f''(x)= 2, f' (-2)=0 dan (-2)=14

InteGraL

f' (x) = ∫f"(x) dx
f'(x) = ∫ 2 dx = 2x + C

f'(-2) = 0
2.(-2) + C = 0
C = 4
➡ f'(x) = 2x + 4

f(x) = ∫f'(x) dx
f(x) = ∫(2x + 4) dx
f(x) = x² + 4x + C

f(-2) = 14
(-2)² + 4(-2) + C = 14
4 - 8 + C = 14
C = 18

➡ f(x) = x² + 4x + 18