integral akar tiga dari (x+1) pangkat 5 dx =

Penyelesaian:

∫ [tex] \sqrt[3]{(x + 1)^5} dx[/tex]
 
y = 3x + 1
dy / dx = 3
dx = dy/3

[tex] \sqrt[3]{(x + 1)^5} dx[/tex]
= ∫ [tex](x + 1)^5/3 dx[/tex]
= ∫ [tex]y^5/3 dy/3[/tex]
= [tex] \frac{1}{3} [/tex] ∫ [tex]y^5/3 dy[/tex]
= [tex] \frac{1}{3} . \frac{3}{8} . y^8/3 + c[/tex]
= [tex] \frac{1}{8} . y^2 . y^2/3 + c[/tex]
= [tex] \frac{1}{8} . y^2 . \sqrt[3]{2} + c[/tex]
= [tex] \frac{1}{8} (x + 1)^2 . \sqrt[3]{(x + 1)^2} + c[/tex]