persamaan nilai mutlak linear satu variabel menggunakan |x|=√x² dari |7x-4|=3 tolong pake cara ya

|7x-4| = 3
(7x-4)² = 3²
49x² - 56x + 16 - 9 = 0
49x² - 56x + 7 = 0
7x² - 8x + 1 = 0
(7x-1)(x-1) = 0
7x-1 = 0
7x = 1
x = 1/7
x-1 = 0
x = 1

HP = {1/7, 1}