Bentuk sederhana dari ............
Matematika
haudam
Pertanyaan
Bentuk sederhana dari ............
1 Jawaban
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1. Jawaban Anonyme
Simplifying.
Nomor 1
[tex]\displaystyle \frac{\sqrt{50}-\sqrt{2}}{2\sqrt{18}}\\ =\frac{5\sqrt{2}-\sqrt{2}}{6\sqrt{2}}\\ =\frac{2}{3}[/tex]
Nomor 2
[tex]\displaystyle \frac{\sqrt{3}+2\sqrt{2}}{\sqrt{18}-\sqrt{12}}\\ =\frac{\sqrt{3}+2\sqrt{2}}{\sqrt{18}-\sqrt{12}}~\frac{\sqrt{18}+\sqrt{12}}{\sqrt{18}+\sqrt{12}}\\ =\frac{18+7\sqrt{6}}{6}[/tex]
Nomor 3
[tex]\displaystyle \frac{4}{\sqrt{20}}+\frac{3}{\sqrt{5}}\\ =\frac{4\sqrt{5}+3\sqrt{20}}{10}\\ =\frac{4\sqrt{5}+6\sqrt{5}}{10}\\ =\sqrt{5}[/tex]