himpunan penyelesaian dari | x + 1 | + | 1 - x |=2

1. |x + 1| + |1-x| = 2
x + 1 + 1 - x = 2
x + 2 - x = 2
x - x = 2 - 2
0 = 0
(tidak mutlak)

2. -|x + 1| + |1-x| = 2
-x - 1 + 1 - x = 2
-2x = 2
x = -1

3. |x + 1| + (-|1-x|) = 2
x + 1 - 1 + x = 2
2x = 2
x = 1

4. |x + 1| + |1-x| = 2
x + 1 + 1 - x = 2
x + 2 - x = 2
x - x = 2 - 2
0 = 0
(tidak mutlak)

Hp :
1. -
2. {x = -1}
3. {x = 1}
4. -