Matematika

Pertanyaan

log72 + log2√5 - log125

1 Jawaban

  • log 72 + log 2√5 - log 125
    = log 72 + log 2 + log √5 - log 125
    = log (72 × 2) + log (5^1/2 /5^3)
    = log (2^4 × 3^2) + log 5^(-5/2)
    = 4log 2 + 2log 3 - 5/2 log 5
    = 4(0,301) + 2(0,477) - 5/2 (0,699)
    = 1,204 + 0,954 - 1,7475
    = 0,4105

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