Jika f(x)=2x²-4x+3 dengan daerah asal A={x/x≤3,x€ bil.cacah}. Tentukan daerah hasil!

A = {0,1,2,3}

f(0) = 2.0^2  - 4.0 + 3 = 0 - 0 + 3 = 3
f(1) = 2.1^2 - 4.1 + 3 = 2 - 4 + 3 = 1
f(2) = 2.2^2 - 4.2 + 3 = 8 - 8 + 3 = 3
f(3)= 2.3^2 - 4.3 + 3 = 18 - 12 + 3 = 9

daerah hasil = 1,3,9

f(x) = 2x^2 - 4x + 3
dengan syarat =
A={x/x≤3,x€ bil.cacah}A = 0, 1, 2, 3
f (0) = 2(0)^2 - 4(0) +3 = 3
f(1) = 2(1)^2 - 4(1) + 3 = 1
f(2) = 2(2)^2 - 4(2) +3 = 3
f(3) = 2(3)^2 - 4 (3) + 3 = 9