2^3 dikali (32×243) pangkat 4/5
Matematika
26062001
Pertanyaan
2^3 dikali (32×243) pangkat 4/5
1 Jawaban
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1. Jawaban SadonoSukirno
2³ × (32 × 243)^4/5
= 2³ × 32^4/5 × 243^4/5
= 2³ × (2^5)^4/5 × (3^5)^4/5
= 2³ × 2^(5×4/5) × 3^(5×4/5)
= 2³ × 2^4 × 3^4
= 2^3+4 × 3^4
= 2^7 × 3^4
= 128 × 81
= 10.368