^3log 6+ ^2log 3 -^3log2 Mohon dijawab

^3log 6+ ^2log 3 -^3log2
^3 log 6/2 + 2log3
= 3log3 + 2log3
= 1 + 2log3
= 2log2(3)
= 3log6

³log6+²log3-³log2
= ³log6-³log2+²log3
= ³log(6:2)+²log3
= ³log3+²log3
= 1+²log3
= ²log2+²log3
= ²log(2×3)
= ²log6
klo ga ngerti bilang aja.
semoga membantu!