tolong dong gak yakin sama jwban saya sndiri.. ( x kuadrat +4x+3 / x) : ( x+4 ) / 4 = ???

[tex] \frac{x^2+4x+3}{x} : \frac{x+4}{4} = \frac{x^2+4x+3}{x} . \frac{4}{x+4} \\ \\ \frac{x^2+4x+3}{x} : \frac{x+4}{4} = \frac{4x^2+16x+12}{x^2+4x} [/tex]

( x^2 + 4x+3/ x) X (4/ (x+4)
4x^2 +16x +12 / x^2+4x
4+4+12
20